Wednesday, June 3, 2009

R.C.C design of slabs and beams manually

R.C.C design of slabs and beams manually

Design of slabs

1) Find the loadings.
a) Live load = LL
b) Dead load = DL
c) Floor finish = FF

2) Find the design load.
Design load = 1.5(LL + DL + FF)

3) Find the edge conditions.
Edge conditions = Ly/Lx

4) Do a deflection check

4) Do a the moment and steel calculation
Coefficients (x and y) are computed as per clause D-1.1 of IS 456:2000:
Mx = x x W x Lx x Lx:
My = y x W x Lx x Lx:
where
Mx,My = moments on strips of unit width spanning Lx and Ly respectively,
W = Total Design Load
Lx = Shorter span
Minimum steel check
As per clause 26.5.2.1 of IS 456:2000:
Minimum area of steel For Main Steel = 0.12 x C/S Area
Notes :
Extra steel at Top support is computed considering
the bent-ups,if any,coming from the adjoining span.
It is the maximum of the extra steel required
for each slab at that common support.

Design of beams

5) Find the loadings.
a) Self weight of beam
b) Slab reaction
Slab reaction = dead load slab reaction and live load slab reaction
c) Wall load
d) Staircase load (if present)

6) Find the total load
Total load = Self weight of beam + Slab reaction + Wall load + Staircase load (if present)


7) Find the area of steel required = Ast

8) Do a check for maximum and minimum steel required

9) Minimum and Maximum Steel Checks :
a)Minimum Steel Check as per IS 456:2000 Clause 26.5.1.1(a)
Ast = (0.85 x b x d) / fy

b) Maximum Steel Check as per IS 456:2000 Clause 26.5.1.1(b)
Ast = 0.04 x b x D
Where,
Fy = strength of steel
B = width of beam
D = depth of beam


10) Do a check for Shear Reinforcement(Stirrups)
Design Shear = (Equivalent S.F.)-(Vuc)
VusT = ( Tu/b1 + Vu/2.5)(d/d1)
Where,
Tu = Torsional moment,
Vu = Ultimate shear force
b1 = Center to center distance between corner bars in the direction of width
d1 = Center to center distance between corner bars in the direction of depth
(As per Clause 41.4.3 of IS 456:2000)
If Design Shear < VusT then Design Shear = VusT
VusT = Minimum shear for torsional transverse Reinforcement
Provide Shear Steel (Stirrups)
Provide minimum Shear Reinforcement of 0.75 d
(As per Clause 26.5.1.5 of IS 456:2000)




2 comments:

  1. We find that using shuttering for the structure is the most cost effective way to construct a structure.
    This is called "total design concept"
    The formwork for these structures included all elements, structural, non- structural, and architectural. The architectural elements include, radius headers, decorative columns, pitched concrete roof, and rain gutters cast directly into the decorative moldings. Casting all elements achieves a cost savings of 10-20% over traditional methods. Casting all elements also speeds construction 30 - 50% over traditional methods. This is achieved by the speed of the formwork system, the reduction follow on trades, and the ease of finishing the surfaces.

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  2. yes.i agree with you.it does reduce the cost

    ReplyDelete